According to equationC6H6(l)+15/2 O2(g)---->6CO2(g)+3H2O(l)AH-3264.4 K

1.	According to equationC6H6(l)+15/2 O2(g)---->6CO2(g)+3H2O(l)AH-3264.4 KJ mol-1 the energy evolved when7.8 g benzene is burnt in air will be(1) 163.22 KJ(3) 3.264 KJ(2) 32.64 KJ(4) 326.4 KJ
Answer» For 1 moles of benzene the value of. ∆H = -3264.4KJ/mol molar mass of benzene is = 78gm so, the energy evolved in 7.8 gm or (7.8/78) = 0.1 moles is = 0.1*(3264.4) = 326.4KJ option D.

According to equationC6H6(l)+15/2 O2(g)---->6CO2(g)+3H2O(l)AH-3264.4 KJ mol-1 the energy evolved when7.8 g benzene is burnt in air will be(1) 163.22 KJ(3) 3.264 KJ(2) 32.64 KJ(4) 326.4 KJ

Answer»

For 1 moles of benzene the value of. ∆H = -3264.4KJ/mol

molar mass of benzene is = 78gm

so, the energy evolved in 7.8 gm or (7.8/78) = 0.1 moles is

= 0.1*(3264.4) = 326.4KJ

option D.