According to equationC6H6(l)+15/2 O2(g)---->6CO2(g)+3H2O(l)AH-3264.4 K – InterviewSolution

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1.	According to equationC6H6(l)+15/2 O2(g)---->6CO2(g)+3H2O(l)AH-3264.4 KJ mol-1 the energy evolved when7.8 g benzene is burnt in air will be(1) 163.22 KJ(3) 3.264 KJ(2) 32.64 KJ(4) 326.4 KJ
Answer» <p>For 1 moles of benzene the value of. ∆H = -3264.4KJ/mol</p><p>molar mass of benzene is = 78gm</p><p>so, the energy evolved in 7.8 gm or (7.8/78) = 0.1 moles is </p><p>= 0.1*(3264.4) = 326.4KJ</p><p>option D.</p>

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