InterviewSolution
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InterviewSolution
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According to following figure, If AB ⊥ BC, DC ⊥ BC and DE ⊥ AC then prove that ∆CED ~ ∆ABC |
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Answer» Given AB ⊥ BC, DC ⊥ BC and DE ⊥ AC To prove : ∆CED ~ ∆ABC Proof : AB ⊥ BC and DC ⊥ BC ∴ AB || DC When AB || DC cuts by transversal AC ∠BAC = ∠ACD or ∠BAC = ∠ECD ∠B = ∠E = 90° (given) …(ii) ∴ ∠ACB = ∠EDC [due to (i) and (ii)] ⇒ ∆ABC ~ ∆CED. |
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