In figure `XY||` seg AC. If `2AX=3BX` and `XY=9`, complete the activity to find the value of AC. Activity: `2AX=3BX` `:.(AX)/(BX)=(square)/(square)` `:.(AX+BX)/(BX)=(square+square)/(square)`.........(By componendo) `:.(AB)/(BX)=(square)/(square)`.............1`DeltaBCA~DeltaBYX`.......(`square` test of similarity) `:.(BA)/(BX)=(AC)/(XY)` ..............(Corresponding sides of similar triangles) `:.(square)/(square)=(AC)/9` `:.AC=square` ...........[From 1]

In figure `XY||` seg AC. If `2AX=3BX` and `XY=9`, complete the activit

1.	In figure `XY\|\|` seg AC. If `2AX=3BX` and `XY=9`, complete the activity to find the value of AC. Activity: `2AX=3BX` `:.(AX)/(BX)=(square)/(square)` `:.(AX+BX)/(BX)=(square+square)/(square)`.........(By componendo) `:.(AB)/(BX)=(square)/(square)`.............1`DeltaBCA~DeltaBYX`.......(`square` test of similarity) `:.(BA)/(BX)=(AC)/(XY)` ..............(Corresponding sides of similar triangles) `:.(square)/(square)=(AC)/9` `:.AC=square` ...........[From 1]
Answer» `2AX=3BX` `:.(AX)/(BX)=3/2` `:.(AX+BX)/(BX)=(3+2)/2` …….(By componendo) `:.(AB)/(BX)=5/2` ………..1 `DeltaBCA~DeltaBYX`……..(AA test of similarity) `:.(BA)/(BX)=(AC)/(XY)` ………….(Corresponding sides of similar triangles) `:.5/2=(AC)/9` `:.AC=22.5`...........[From 1]

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In figure `XY||` seg AC. If `2AX=3BX` and `XY=9`, complete the activity to find the value of AC. Activity: `2AX=3BX` `:.(AX)/(BX)=(square)/(square)` `:.(AX+BX)/(BX)=(square+square)/(square)`.........(By componendo) `:.(AB)/(BX)=(square)/(square)`.............1`DeltaBCA~DeltaBYX`.......(`square` test of similarity) `:.(BA)/(BX)=(AC)/(XY)` ..............(Corresponding sides of similar triangles) `:.(square)/(square)=(AC)/9` `:.AC=square` ...........[From 1]
In the adjoining figure, seg `XY||` seg `AC`, IF `3AX=2BX` and `XY=9` then find the length of `AC`.

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