According to Newton’s law of cooling ms (d theta)/(dt)=-K(theta-theta_0). If sigma is Stefan’s constant, A is surface area of the body and T_@ is temperature of surroundings in K, then the value of K on the basis of Stefan-Boltzmann law is –

According to Newton’s law of cooling ms (d theta)/(dt)=-K(theta-thet

1.	According to Newton’s law of cooling ms (d theta)/(dt)=-K(theta-theta_0). If sigma is Stefan’s constant, A is surface area of the body and T_@ is temperature of surroundings in K, then the value of K on the basis of Stefan-Boltzmann law is –
Answer» `SIGMA AT_(0)^4` `sigma AT_0^3` `4sigma AT_0^4` `4sigma A T_0^3` ANSWER :D

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According to Newton’s law of cooling ms (d theta)/(dt)=-K(theta-theta_0). If sigma is Stefan’s constant, A is surface area of the body and T_@ is temperature of surroundings in K, then the value of K on the basis of Stefan-Boltzmann law is –

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