According to the first law of thermodynamics, `DeltaU=q+w`. In special cases the statement can be expressed in different ways. Which of the following is not a correct expression ?A. At constant temperature, `q=-w`B. When no work is done , `DeltaU=q`C. In gaseous system , `DeltaU=q+PDeltaV`D. When work is done by the system : `DeltaU=q+w`

According to the first law of thermodynamics, `DeltaU=q+w`. In special

1.	According to the first law of thermodynamics, `DeltaU=q+w`. In special cases the statement can be expressed in different ways. Which of the following is not a correct expression ?A. At constant temperature, `q=-w`B. When no work is done , `DeltaU=q`C. In gaseous system , `DeltaU=q+PDeltaV`D. When work is done by the system : `DeltaU=q+w`
Answer» Correct Answer - D When work is done by the system, `DeltaU=q-w`.

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