1.

According to the reaction PbCl_(2) = Pb^(2) + 2Cl^(-), the solubility coefficient of PbCl_(2) is

Answer»

`[PB^(2+)] [Cl^(-)]^(2)`
`[Pb^(2+)] [Cl^(-)]`
`[Pb^(2+)]^(2) [Cl^(-)]`
NONE of these

Solution :Solubility coefficient `= [Pb^(2+)] [Cl^(-)]^(2)`.


Discussion

No Comment Found