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Account for (CH_3)_2NH requires two moler proportion of CH_2I to give the same crystalline product formed by (CH_3)_2N with one mole of CH_3I. |
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Answer» Solution :`(CH_3)_2NH` (Secondary AMINE) REQUIRES 2 MOLES of `CH_3I`to give a quatermary salt (crystalline PRODUCT) whereas `(CH_3)_2N` (tertiary amine) require only one mole of `CH_3I` to give the same quaternary salt. It is due to the number of alkyl groups present in amines. `{:((CH_3)_2-NH+2CH_2I to [(CH_3)_4]^+I^-),("Secondary amineTetramethyl ammonium iodide "):}`. |
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