Saved Bookmarks
| 1. |
Account for the fact that [Ni(CO)_(4)] has tetrahedral geometry whereas [Ni(CN)_(4)]^(2-) has square planar geometry. |
| Answer» Solution :In `[Ni(CO)_(4)]`, Ni is `sp^(3)` hybridised but in `[Ni(CN)_(4)]^(2-)` it is `dsp^(2)` hybridised. | |