1.

Account for the fact that [Ni(CO)_(4)] has tetrahedral geometry whereas [Ni(CN)_(4)]^(2-) has square planar geometry.

Answer»

Solution :In `[Ni(CO)_(4)]`, Ni is `sp^(3)` hybridised but in `[Ni(CN)_(4)]^(2-)` it is `dsp^(2)` hybridised.


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