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Account for the following: (i) In the series Sc to Zn, the enthalpy of atomisation of zinc is the lowest. (ii) The E^0 value for the Mn^(3+)//Mn^(2+) couple is much more positive than that for Cr^(3+)//Cr^(2+). |
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Answer» Solution :(i) In the series Sc to Zn, the enthalpy of atomisation DECREASES from left to right. ZINC has fully filled 3d sub shell with inter atomic electronic bonding is weakest in Zn. Therefore zinc has lowest enthalpy of atomisation. (ii) In the electrochemical series, the SUBSTANCE are ARRANGED in the increasing order of reduction potential. The`E^0` for `MN^(3+)//Mn^(2+)` is more positive than Eo for `Cr^(3+)//Cr^(2+)`, because Mn has greater tendency to get reduced as compared to Cr. This is why Mn is below Cr in electrochemical series. |
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