1.

∠ACD is an exterior angle of ∆ABC. m∠A = 70° and m∠ACD = 120°. Find m ∠B and m ∠ACB.

Answer»

angle B= 50 DEGREES. angle ACB = 60 degreesStep-by-step EXPLANATION:by exterior angle property,angle A + angle B = angle ACD70+ angle B= 120angle B= 50 degreesBy angle sum property of a TRIANGLE,angle A + angle B + angle ACB = 180 degrees70+50+angle ACB=180angle ACB= 60 degrees



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