1.

Acetaldehyde and acetone can be distinguished by

Answer»

MOLISCH test
Bromoform test
Solubility in water
Tollen's test

Solution :`CH_(3)CHO overset([AG(NH_(3))_(2)])rarrCH_(3)COOH+underset("Silver mirror RED")(Ag_(darr)+NH_(3))`
While acetone do not react.


Discussion

No Comment Found