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Acetic acid associates as dimers in benzene. What is the Van’t Hoff factor (i) if the degree of association of acetic acid is 50%?(a) 0.25(b) 0.50(c) 0.75(d) 0.40I had been asked this question at a job interview.Query is from Abnormal Molar Masses topic in section Solutions of Chemistry – Class 12

Answer»

Correct option is (C) 0.75

Explanation: Given,

Degree of association (α) = 50% = 0.5

Number of molecules ASSOCIATED (n) = 2

Let the Van’t Hoff factor = i

We KNOW that for solutes that associate in SOLUTION, i = 1 + ((1/n) -1) x α

= 1 + ((1/2) – 1) x 0.5

= 1 – (0.5 x 0.5)

= 0.75

Therefore, the Van’t Hoff factor is equal to 0.75.



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