1.

Acidified K_2 Cr_2 O_7 turns green by

Answer»

`SO_(2)`
CO
`SiO_(2)`
`HCl`

SOLUTION :`K_(2)Cr_(2)O_(7)` turns green by `SO_(2)` DUE to its reduction
`K_(2)Cr_(2)O_(7)+H_(2)SO_(4)+3SO_(2) to K_(2)SO_(4)+underset("Green")(Cr_(2)(SO_(4))_(3))+H_(2)O`


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