1.

Acidified K_2Cr_2O_7 changes to green on reactions with

Answer»

`SO_2`
`FeSO_4`
Kl and then ADDING HYPO
`NaCl + CONC. H_2SO_4`

Solution :`Cr_(2)O_(7)^(-2) + SO_(2) rarr UNDERSET("(green)")(Cr_2(SO_4)_3`
`Cr_2O_7^(-2) + FE^(+2) rarr Cr^(+3) +Fe^(+3)`


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