1.

Activation energy (E_(a)) and rate constant (K_(1) and (K_(2)) for a chemical reaction at two different temperatures T_(1) and T_(2) are related by:

Answer»

In `K_(2)/K_(1) = E_(a)/R(1/T_(1) - 1/T_(2))`
In `k_(2)/k_(1) = -E_(a)/R(1/T_(2)-1/T_(1))`
In `k_(2)/k_(1) = -E_(a)/R(1/T_(2)+1/T_(1))`
In `k_(2)/k_(1) = E_(a)/R(1/T_(1)-1/T_(2))`

SOLUTION :b,d) Both options are correct.


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