1.

Activation energy (E_(a)) and rate constants (K_(1) and K_(2)) of a chemical reaction at two different temperatures (T_(1) and T_(2) ) are related by

Answer»

LN `(K_(2))/(K_(1)) = - (E_(a))/ ( R) ((1)/(T_(1)) - (1)/(T_(2)))`
ln `(K_(2))/(K_(1)) = (E_(a))/ ( R) ((1)/(T_(1)) - (1)/(T_(2)))`
ln `(K_(2))/(K_(1)) = - (E_(a))/ ( R) ((1)/(T_(1)) + (2)/(T_(1)))`
ln `(K_(2))/(K_(1)) = - (E_(a))/ ( R) ((1)/(T_(2)) - (1)/(T_(1)))`

Solution :Arrhenius equation
ln `(K_(2))/(K_(1)) = (E_(a))/(R) ((1)/(T_(1)) - (1)/(T_(2)))`
ln `(K_(2))/(K_(1)) = - (E_(a))/(R) ((1)/(T_(2)) - (1)/(T_(1)))`


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