Activation energy of a chemical reaction can be determined byA. evaluting rate constant at standard temperatureB. evaluting velocities of reaction at two different temperaturesC. evaluating rate constants at two different temperaturesD. changing concentration of reactants

Activation energy of a chemical reaction can be determined byA. evalut

1.	Activation energy of a chemical reaction can be determined byA. evaluting rate constant at standard temperatureB. evaluting velocities of reaction at two different temperaturesC. evaluating rate constants at two different temperaturesD. changing concentration of reactants
Answer» Correct Answer - C According to Arrhenius equation `k=Ae^(-E_(a)//RT)` Taking natural logarithm of both sides, we get `Ink=InA-(E_(a))/(RT)` At temperature `T_(1))` , equation becomes `Ink_(1)=InA-(E_(a))/(RT_(1)` At temperature `T_(2))` , equation becomes `Ink_(1)=InA-(E_(a))/(RT_(1)` (Since `A` is constant for a given reaction). `K_(1)` and `k_(2)` are the value of rate constant at temperature `T_(1)` and `T_(2)` respectively. Subtracting equation `(1)` from equation `(2)` , we obtain `Ink_(2)-Ink_(1)=(-(E_(a))/(RT_(2)))-(-(E_(a))/(RT_(1)))` `In(k_(2))/(k_(1))=-(E_(a))/(R)((1)/(T_(2))-(1)/(T_(1)))` or log`(k_(2))/(k_(1))=-(E_(a))/(2.303R)((1)/(T_(2))-(1)/(T_(1)))` or log`(k_(2))/(k_(1))=(E_(a))/(2.303R)((T_(2)-T_(1))/(T_(1)T_(2)))` Thus, we can evaluate the activation energy of a chemical reaction by knowing rate constants `(k_(1) and k_(2))` at two differences temperatures `(T_(1) and T_(2))` .

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Activation energy of a chemical reaction can be determined byA. evaluting rate constant at standard temperatureB. evaluting velocities of reaction at two different temperaturesC. evaluating rate constants at two different temperaturesD. changing concentration of reactants

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