Activity: A bag contains 3 red and 5 white balls. Two balls are drawn

1.	Activity: A bag contains 3 red and 5 white balls. Two balls are drawn at random one after the other without replacement. Find the probability that both the balls are white.
Answer» Let, event A: The first ball drawn is white event B: Second ball drawn is white. P(A) = 5/8 After drawing the first ball, without replacing it into the bag a second ball is drawn from the remaining 7 balls. ∴ P(B/A) = 4/7 ∴ P(Both balls are white) = P(A ∩ B) = P(A) . P(B/A) = 5/8 x 4/7 = 5/14

Activity: A bag contains 3 red and 5 white balls. Two balls are drawn at random one after the other without replacement. Find the probability that both the balls are white.

Answer»

Let, event A: The first ball drawn is white

event B: Second ball drawn is white.

P(A) = 5/8

After drawing the first ball, without replacing it into the bag a second ball is drawn from the remaining 7 balls.

∴ P(B/A) = 4/7

∴ P(Both balls are white) = P(A ∩ B)

= P(A) . P(B/A)

= 5/8 x 4/7

= 5/14

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Activity: A bag contains 3 red and 5 white balls. Two balls are drawn at random one after the other without replacement. Find the probability that both the balls are white.

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