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Add the following: (i) 5a2b2+10ab−12a2+15b−20 and 34ab+24a2+22b+24 (ii) abc+6bcd+abd−9ab+4bc−9a−43 and 4acd+10ac−54b−32c (iii) 5bc+9ad−3c−12 and 24−5c−5b+2ab [4 MARKS] |
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Answer» Add the following: |
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