Addition of 0.643 g of a compound to 50 mL of benzene (density : 0.879 – InterviewSolution

1.	Addition of 0.643 g of a compound to 50 mL of benzene (density : 0.879 g/ml) lowers the freezing point from 5.51^(@)C to 5.03^(@)C. If K_(f) for benzene is 5.12,calculate the molecular weight of the compound.
Answer» SOLUTION :`w_(2)=0.643g, w_(1)=50xx0.879 G = 43.95g.`

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