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1. |
Addition of `Cl_(2) to KI solution give its a brown colour but excess of cl_(2) ` turns it colourless. Why? |
Answer» The initial brown colour is due to relase of `I_(2)` from the solution. But excess of chlorine dissolves iodine to form a colourless compound iodic acid. `Cl_(2)+2KI to 2KCl+ underset(("Brown"))(I_(2))` `5Cl_(2)+I_(2)+6H_(2)O to 10 HCl + underset(("Colourless"))(2HIO_(3))` |
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