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Addition of H_(2) to accetylene gives ethane in presence of palladium but if BaSO_(4) and quinoline or sulphur are also added, the product is ethane. Why ? |
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Answer» Solution :`CH-=CH+H_(2)overset(Pd)tounderset("Ethene")(CH_(2)=CH_(2))overset(""^(+)H_(2))UNDERSET(Pd)tounderset("Ethane")(CH_(3)-CH_(3))` `CH-=CH+H_(2)overset(Pd+BaSO _(4))underset(+"quinoline/S")tounderset("Ethene")(CH_(2)=CH_(2))` `BaSO_(4)+` quinoline/S posion the catalyst. Hence th efficiency of the catalyst decreases and the reaction stops at the first stagte of REDUCTION. |
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