Adjacent sides of a triangle are x-4xy+7y and x-5xy find its area.

1.	Adjacent sides of a triangle are x-4xy+7y and x-5xy find its area.
Answer» Reqd. area = (x2 – 4xy + 7y2) (x3 – 5XY2) = x2(x3 – 5xy2) – 4xy (x3 – 5xy2) + 7y2 (x3 – 5xy2) = x5 – 5x3y2 – 4x4y + 20x2y3 + 7x3y2 – 35xy4 = x5 + (7 – 5)x3y2 – 4x4y + 20x2y3 – 35xy4 = x5 + 2x3y2 – 4x4y + 20x2y3 – 35xy4 = (x5 – 4x4y + 2x3y2 + 20x2y3 – 35xy4) SQ. unit. it is a same TYPE of question

Answer»

Reqd. area = (x2 – 4xy + 7y2) (x3 – 5XY2)

= x2(x3 – 5xy2) – 4xy (x3 – 5xy2) + 7y2 (x3 – 5xy2)

= x5 – 5x3y2 – 4x4y + 20x2y3 + 7x3y2 – 35xy4

= x5 + (7 – 5)x3y2 – 4x4y + 20x2y3 – 35xy4

= x5 + 2x3y2 – 4x4y + 20x2y3 – 35xy4

= (x5 – 4x4y + 2x3y2 + 20x2y3 – 35xy4) SQ. unit.

it is a same TYPE of question

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