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After 2 hours the amount of a certain radioactive substance reduces to `1//16^(th)` of the original amount (the decay process follows first-order kinetics). The half-life of the radioactive substance isA. 15 minB. 30 minC. 45 minD. 60 min |
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Answer» Correct Answer - B `(0.693)/(t_(1//2))=(2.303)/(2xx60)log. (a)/(a//16)` `t_(1//2)=30 min` |
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