1.

After 24 hour, only 0.125" g" out of the initial quantity of 1 g of a radioactive isotope remains behind. The half-life period of the radioactive isotope in hours is

Answer»

`7.2 h`
`7.99 h`
`6.99 h`
`10.0 h`

Solution :In this problem , 'a'=1.0g and 'a-x'=0.125gand 't'=24h. Therefore,the DISINTEGRATION CONSTANT.
`lambda= (2.303)/(t) "log" (a)/(a-x)`
Or `lambda =(2.303)/(24)"log" (1)/(0.125)=0.0866h^(-1) " "` Or `" " t_(1//2)=(0.693)/(0.0866)=7.99` hours


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