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After 24 hours, only 0.125 g out of the initial quantity of 1g of a radioisotope remains behind. what is half-life period? |
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Answer» Solution :`N_(0)` N=0.125 G ,t=24 HOURS `therefore lambda =(2.303)/(t)log(N_(0))/(N)` `=(2.303)/(24) log (1)/(0.25)` `therefore t^(1//2) =(0.693)/(lambda)=(0.639)/(0.866)=7.99` hours |
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