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After absorbing a slowly moving neutron of Mass m_(N) (momentum ~~0 ) a nucleus of mass M breaks into two nuclei of masses m_(1)and5m_(1) (6m_(1)=M+m_(N)) respectively. If the de Broglie wavelength of the nucleus with mass m_(1) is lamda the de Broglie wavelength of the nucleus will be |
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Answer» `5lamda` `P_(1)=P+P_(2)` `P_(1)=P_(2)` `0+P_(1)+P_(2)` `(P_(1)=-P_(2))` `lambda_(1)=(H)/(P_(1))` `lambda_(2)=(h)/(P_(2))` `|lambda_(1)|=|lambda_(2)|` `lambda_(1)=lambda_(2)` |
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