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After absorbing a slowly moving neutrons of mass `m_(N)` (momentum ~0) a nucleus of mass M breaks into two nucleii of mass `m_(1) and 5m_(1)(6m_(1)=M+m_(N))`, respectively . If the de-Broglie wavelength of the nucleus with mass `m_(1) ` is ` lambda`, then de Broglie wavelength of the other nucleus will beA. `5 lambda`B. `lambda//5`C. `lambda`D. `25 lambda` |
Answer» Correct Answer - C `P_(i)=0` `P_(f)=P_(1)+P_(2)` `P_(i)=P_(f)` `0=P_(1)+P_(2)` `(P_(1)=-P_(2))` `lambda_(1)=(h)/(P_(1))` `lambda_(2)=(h)/(P_(2))` `|lambda_(1)|=|lambda_(2)|` `lambda_(1)=lambda_(2)=lambda` |
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