1.

After how many seconds will the concentration of the reactants in a first order reaction be halved . If the decay constant is 1.155 xx 10^(-3) sec^(-1)

Answer»

100 sec
200 sec
400 sec
600 sec

SOLUTION :`t = (2.303)/(k)` LOG `(a)/(a-x)`
`t = (2.303)/(1.155 xx 10^(-3)) "log" (100)/(100-50) = 600` sec.


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