1.

After the emission of one alpha-particle followed by one beta-particle from the atom of ._(92)X^(238), the number of neutrons in the atom will be

Answer»

142
146
144
143

Solution :`._(92)X^(238) overset(-alpha)RARR ._(90)Y^(234)overset(-beta)rarr ._(91)Z^(234)`
no. of neutrons `= 234 - 91 = 143`


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