After time t, the height y of a projectile is Y = 8t -5t^2 and horizontal distance x = 6 t ifg = 10m//s^2 the velocity of the projectile at the instant is

After time t, the height y of a projectile is Y = 8t -5t^2 and horizon

1.	After time t, the height y of a projectile is Y = 8t -5t^2 and horizontal distance x = 6 t ifg = 10m//s^2 the velocity of the projectile at the instant is
Answer» 8 m `s^-1` 10 m `s^-1` 6 m `s^-1` 4 m `s^-1` Answer :B

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After time t, the height y of a projectile is Y = 8t -5t^2 and horizontal distance x = 6 t ifg = 10m//s^2 the velocity of the projectile at the instant is

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