1.

Ag_(2)S+NaCN+Zn to Ag+W In W the corrdination number of Z in

Answer»


SOLUTION :`Ag_(2)S+4NaCN hArr 2NA[AG(CN_(2))]+Na_(2)S`
`4Na_(2)S+5O_(2)+2H_(2)O to 2Na_(2)SO_(4)+4NaOH+2S`
`2Na[Ag(CN)_(2)]+Zn to Na_(2) underset((A))[Zn(CN)_(4)]+2Ag`
In the compound ()A the coordination number of zn is 4.


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