1.

Ag^(+)+NH_(3)iff[Ag(NH_(3))]^(+),k_(1)=6.8xx10^(-3) [Ag(NH_(3))]^(+)+NH_(3)iff[Ag(NH_(3))_(2)]^(+),k_(2)=1.6xx10^(-3)then the formation constant of [Ag(NH_(3))_(2)]^(+) is

Answer»

`1.08xx10^(-7)`
`1.08xx10^(-5)`
`1.08xx10^(-9)`
none of these

Solution :As the REACTION TAKES placein two steps.
`beta=beta_(1)xxbeta_(2)=(6.8xx10^(-3))XX(1.6xx10^(-3))=10.8xx10^(-6)=1.08xx10^(-5)`


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