1.

AgNO_(2)(aq) was added to an aqueous KCl solution gradually and the conductivity of the solution was measured. The plot conductivity of the solution was measured. The plot of conductance (wedge) versus the volume of AgNO_(3) is

Answer»

`P`
`Q`
`R`
`S`

Solution :`AgNO_(3)(aq)+KCl(aq) rarr AgCldarr+KNO_(3)(aq)`
In this reaction, `Cl^(c-)` ions are relaced by `NO_(3)^(c-)` ions.
`i.` Till all `KCl(Cl^(c-)` ions `)` gets CONSUMED by `NO_(3)^(c-)` ions, `Cl^(c-)` will get REPLACED by `NO_(3)^(c-)` ion.
`K^(o+)Cl^(c-) overset(AgNO_(3))rarrK^(o+)NO_(3)^(c-)`.
Conductance is constant since the conductance `(wedge)` of `Cl^(c-)~~` conductance of `NO_(3)^(c-)`.
Initially, conductance do not fall of to a large extent. Even the fall `//` rise will be linear `(` either DECREASING or increasing `)`.
`ii.` When all `Cl^(c-)` ions are reacted and no reaction occurs, there are `AG^(o+), NO_(3)^(c-)`, and `K^(o+)` ions are left in the solution which increases the conductance of solution sharply.
`K^(o+)Cl^(c-) overset(AgNO_(3))rarr Ag^(o+)+K^(o+)+NO_(3)^(c-)`
Hence, graph`(s)` is the most appropriate answer.


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