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`AIF_(3)` is soluble in `HF` only in presence of `KF`. It is due to the formation ofA. `K_(3)[AlF_(3)H_(3)]`B. `K_(3)[AlF_(6)]`C. `AlH_(3)`D. `K[AlF_(3)H]` |
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Answer» Correct Answer - B KF dissociate to give `F^(-)` and form soluble complex with `AlF_(3)` ltBrgt `AlF_(3)+3KF to K_(3)[AlF_(6)]` |
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