1.

AinyopicaduIthasafarpointatO.l m. His power of accomodation is 4D. What is his near point with out glasses? (Take the image distance from the lens of the eye to the retina to be 2 cm)

Answer»

0.07 m
0.7 m
7 m
0.007m

Solution :For the normal eye his power of ACCOMODATION is 4D. let the power of the normal eye for near VISION be `P_(n)`
Then, 4 =`P_(n)-P_(f)` or `P_(n)`=64D
Let his near point be `x_(n)` , then
`1/x_(n) + 1/0.02 = 64` or `1/(x_(n)+50) = 64`
`1/x_(n) = 14 implies x_(n) = 1/14m = 0.07`m


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