Air in the cyclinder of a diesel engine is compressed to `1/15` of its initial volume. If initial temperature is `300K` and initial pressure is `10^(5)Pa`, find the final temperature and final pressure. Take `gamma= 1.4`.

Air in the cyclinder of a diesel engine is compressed to `1/15` of its

1.	Air in the cyclinder of a diesel engine is compressed to `1/15` of its initial volume. If initial temperature is `300K` and initial pressure is `10^(5)Pa`, find the final temperature and final pressure. Take `gamma= 1.4`.
Answer» Here, `(V_(2))/(V_(1))= 1/15, P_(1)= 10^(5)Pa`, `T_(1)=300K, T_(2)=?, P_(2)=?` In an adiabatic process, `P_(2)V_(2)^(gamma)= P_(1)V_(1)gamma` `:. P_(2)=P_(1)((V_(1))/(V_(2)))^(gamma)` `P_(2)=10^(5)(15)^(1.4)= 44.3xx10^(5)Pa` Also, `T_(2)V_(2)^(gamma-1)= T_(1)V_(1)^(gamma-1)` `T_(2)=T_(1)((V_(1))/(V_(2)))^(gamma-1) = 300(15)^(1.4-1)= 886K`

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Air in the cyclinder of a diesel engine is compressed to `1/15` of its initial volume. If initial temperature is `300K` and initial pressure is `10^(5)Pa`, find the final temperature and final pressure. Take `gamma= 1.4`.

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