InterviewSolution
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InterviewSolution
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Air is pumped into the tubes of a cycle rickshaw at a pressure of 2atm. The volume of each tube at this pressure is `0.002m^(3). One of the tubes gets punctured and the vloume of the tube reduces to `0.0005m^(3)`.How many moles of air have leaked out? Assume that the temperature remains constant at 300K abd that the air behaves asan ideal gas. |
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Answer» `P_1 = 2 atm = 2 xx (10^5)Pa` ` V_1 = 0.002(m^3), T_1 = 300K` ` (P_1)(V_1) = (n_1)(RT_1)` ` rArr (n_1) = ((P_1)(V_1)/ (RT_1)) = (2 xx (10^5)xx 0.002/ 8.3 300)` ` = (2 xx (10^5) xx 2 xx (10^-3)/ 8.3 xx (10^2) xx 3)` ` = (4/ 8.3 xx 3) = 0.1606.` ` Again, (P_2) = 1 atm = 10^5Pa` ` V_2 = 0.0005 (m^3), (T_2)= 300K` ` ((P_2)(V_2))= (n_2)(RT_2)` ` rArr (n_2) = ((P_2)(V_2)/(RT_2)) = ((10^5) xx 0.0005 / 8.3 xx 300)` ` = ((10^5) xx 5 xx (10^-4)/ 8.3 xx 3 xx (10^2))` ` = (5/ 3 xx 83) = 0.02` ` Delta m = moles leaked out ` ` = 0.16 - 0.02 = 0.14` . |
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