1.

AlCl_(2) is solubleis axcessof NaOH formingsodiummetaaluminate Na[Al(OH)_(4)].

Answer»


Solution :`AICI_(3) + NaOH RARR 3NaCI + AI(OH)_(3) DARR`
`AI(OH)_(3) + NaOHrarr underset("Soluble")(Na[AI(OH)_(4)])`
HENCE true.


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