1.

All Cu(II) halides are known except iodide. The reason for this is that

Answer»

iodide ION is a bulkyion
`CU^(2+)` oxidizes iodide to iodine
`Cu^(2+) ` (aq) has much more negative hydration enthalpy
`Cu^(2+)` ion has smaller size

Solution :Iodide `(I^(-))` ions are stronger REDUCING agent. They reduce `Cu^(2+)` to `Cu^(+) ( 2CuI_(2) RARR Cu_(2)I_(2)+ I_(2))` In other words, `Cu^(2+)`oxidizes `I^(-)` ions to`I_(2)`
`(2Cu^(2+) + 4I^(-) rarrCu_(2)I_(2)(s)+ I_(2))`


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