1.

All reactions are of 1st order . At time t=t_1(t_1gt0) ([B])/([C])=alphaTherefore at timet=t_2 (where t_2get_1) ([C])/([D])=betaWhich of the following is correct ?

Answer»

`ALPHA gt BETA`
`alpha=beta`
`alphabeta=0.4`
`alpha+beta=0.4`

Solution :`[[B]]/[[C]]=(3k_1)/(8k_1)=3/8=alpha` (at any time)
`[[C]]/[[D]]=(8k_1)/(7.5k_2)=8/7.5=beta` (at any time)
`:. alphabeta=0.4`


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