All red face cards are removed from a pack of playing cards. The remai

1.	All red face cards are removed from a pack of playing cards. The remaining cards are well shuffled and then a card is drawn at random from them. Find the probability that the drawn card is (i) a red card (ii) a face card and (iii) a card of clubs.
Answer» Total number of possible outcomes, n(S) = 52 – 6 = 46 (i) Number of favorable outcomes, n(E) = 26 – 6 = 20 ∴ P(E) = \(\frac{n(E)}{n(S)}\) = \(\frac{20}{46}\) = \(\frac{10}{23}\) (ii) Number of favorable outcomes, n(E) = 12 – 6 = 6 ∴ P(E) = \(\frac{n(E)}{n(S)}\) = \(\frac{6}{46}\) = \(\frac{3}{23}\) (iii) Number of favorable outcomes, n(E) = 13 – 3 = 10 ∴ P(E) = \(\frac{n(E)}{n(S)}\) = \(\frac{10}{46}\) = \(\frac{5}{23}\)

All red face cards are removed from a pack of playing cards. The remaining cards are well shuffled and then a card is drawn at random from them. Find the probability that the drawn card is (i) a red card (ii) a face card and (iii) a card of clubs.

Answer»

Total number of possible outcomes, n(S) = 52 – 6 = 46

(i) Number of favorable outcomes, n(E) = 26 – 6 = 20

∴ P(E) = \(\frac{n(E)}{n(S)}\) = \(\frac{20}{46}\) = \(\frac{10}{23}\)

(ii) Number of favorable outcomes, n(E) = 12 – 6 = 6

∴ P(E) = \(\frac{n(E)}{n(S)}\) = \(\frac{6}{46}\) = \(\frac{3}{23}\)

(iii) Number of favorable outcomes, n(E) = 13 – 3 = 10

∴ P(E) = \(\frac{n(E)}{n(S)}\) = \(\frac{10}{46}\) = \(\frac{5}{23}\)

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All red face cards are removed from a pack of playing cards. The remaining cards are well shuffled and then a card is drawn at random from them. Find the probability that the drawn card is (i) a red card (ii) a face card and (iii) a card of clubs.

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