1.

All the element from nitrogen family have two paired s-electron and three unpaired p-electron in their valence shell thus exhibit three covalence, by sharing of three electron pair to attain stable noble gas configuration except nitrogen all have got vacant d-orbital. All the element of this group exhibit +3 oxidation state in hydride. The tendency to show-3 ionic nature is not possible due to high energy consideration. However, nitrogen being smallest and most electronegative and thus forms N^(3) ion in nitrides such as Mg_(3)N_(2). Ca_(3)N_(2) etc. Rest of all shows -3 oxidation state in covalent compounds. The +3 oxidation state are covalent and ionic both. The +5 oxidation states are covalent as they can not from M^(+5) ions due to high energy involve there in. The tendency to show M^(+3) ionic state however increase down the group due to inert pair effect. Pick up incorrect statement:

Answer»

`PH_(4)^(+)` ion tetrahedral LIKE `NH_(4)^(+)` and is obtained when `PH_(3)` is bonded to proton.
`PH_(4)I` is most stable containing phosphonium ion, it is also more stable than ammonium salt.
`PH_(4)l` is a decomposed by WATER to form `PH_(3)`.
`PH_(3)` converts SILVER salts in solution to silver phosphide which subsequently reach to give free metal.

Answer :B


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