All the element from nitrogen family have two paired s-electron and three unpaired p-electron in their valence shell thus exhibit three covalence, by sharing of three electron pair to attain stable noble gas configuration except nitrogen all have got vacant d-orbital. All the element of this group exhibit +3 oxidation state in hydride. The tendency to show-3 ionic nature is not possible due to high energy consideration. However, nitrogen being smallest and most electronegative and thus forms N^(3) ion in nitrides such as Mg_(3)N_(2). Ca_(3)N_(2) etc. Rest of all shows -3 oxidation state in covalent compounds. The +3 oxidation state are covalent and ionic both. The +5 oxidation states are covalent as they can not from M^(+5) ions due to high energy involve there in. The tendency to show M^(+3) ionic state however increase down the group due to inert pair effect. The most unstable hydride among the following is:

All the element from nitrogen family have two paired s-electron and th

1.	All the element from nitrogen family have two paired s-electron and three unpaired p-electron in their valence shell thus exhibit three covalence, by sharing of three electron pair to attain stable noble gas configuration except nitrogen all have got vacant d-orbital. All the element of this group exhibit +3 oxidation state in hydride. The tendency to show-3 ionic nature is not possible due to high energy consideration. However, nitrogen being smallest and most electronegative and thus forms N^(3) ion in nitrides such as Mg_(3)N_(2). Ca_(3)N_(2) etc. Rest of all shows -3 oxidation state in covalent compounds. The +3 oxidation state are covalent and ionic both. The +5 oxidation states are covalent as they can not from M^(+5) ions due to high energy involve there in. The tendency to show M^(+3) ionic state however increase down the group due to inert pair effect. The most unstable hydride among the following is:
Answer» `NH_(3)` `PH_(3)` `AsH_(3)` `BiH_(3)` Answer :D