1.

All the energy released from the reaction XtoY,Delta_(r)G^(@)=-193" kJ "mol^(-1) is used for oxidizing M^(+) as M^(+)toM^(3+)+2e^(-),E^(@)=-0.25V. Under standard conditions, the number of moles of M^(+) oxidized when one mole of X is converted to Y is (F=96500" C "mol^(-1)).

Answer»


Solution :`XtoY,Delta_(r)G^(@)=-193" kJ "mol^(-1)`. . . (i)
`M^(+)toM^(3+)+2E^(-),E^(@)=-0.25V`
For this reaction, `DeltaG^(@)=-nFE^(@)`
`=-2xx96500xx(-0.25)=48250" J "mol^(-1)`
`=48.25" kJ "mol^(-1)`
i.e., 48.25 kJ of energy is used for oxidizing 1 mole of `M^(+) ` to `M^(3+)`
`therefore` No. of moles of `M^(+)` oxidized by 193 kJ of energy `=(193)/(48.25)=4`


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