1.

All the following complex ions are found to be paramagnetic P=[FeF_(6)]^(3-)Q=[CoF_(6)]^(3-)R=[V(H_(2)O)_(6)]^(3+)S=[T:(H_(2)O)_(6)]^(3+) The correct order of their paramagnetic moment (spin only) is

Answer»

`PgtQgtRgtS`
`PltQltRltS`
P=Q=R=S
`PgtRgtQgtS`

Solution :Both F and `H_(2)O` are WEAK field ligands. So no regrouping of ELECTRONS occurs. HENCE the unpaired electrons will be LEFT as such (5, 4, 2, 1)


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