Alpha particles of mass 6.68 × 10^-27 Kg and charge 3.2 × 10^-19 C is accelerated in a cyclotron in which a magnetic field of 1.25 T is applied perpendicular to the dees. How rapidly should the electric field between the dees be reversed?(a) 5.25 × 10^-8 s(b) 955.25 × 10^-8 s(c) 55.25 × 10^-8 s(d) 575.25 × 10^-8 sI got this question during a job interview.I'd like to ask this question from Motion in Combined Electric and Magnetic Field in chapter Moving Charges and Magnetism of Physics – Class 12

Alpha particles of mass 6.68 × 10^-27 Kg and charge 3.2 × 10^-19 C i

1.	Alpha particles of mass 6.68 × 10^-27 Kg and charge 3.2 × 10^-19 C is accelerated in a cyclotron in which a magnetic field of 1.25 T is applied perpendicular to the dees. How rapidly should the electric field between the dees be reversed?(a) 5.25 × 10^-8 s(b) 955.25 × 10^-8 s(c) 55.25 × 10^-8 s(d) 575.25 × 10^-8 sI got this question during a job interview.I'd like to ask this question from Motion in Combined Electric and Magnetic Field in chapter Moving Charges and Magnetism of Physics – Class 12
Answer» The correct answer is (a) 5.25 × 10^-8 s The EXPLANATION is: Time PERIOD, t = \(\frac {\pi m}{qB}\) t = \(\frac {(3.14 \, \times \, 6.68 \, \times \, 10^{-27})}{(3.2 \, \times \, 10^{-19} \, \times 1.25)}\) t = 5.25 × 10^-8 s.

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