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`alphaa n dbeta`are the positive acute angles and satisfying equation `5sin2beta=3s in2alphaa n dtanbeta=3tanalpha`simultaneously. Then the value of `tanalpha+tanbeta`is _________ |
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Answer» Correct Answer - 4 `5 xx (2 tanbeta)/( 1+ tan^(2) beta ) = 3xx ( 2tan alpha)/(1+tan^(2) alpha )` or ` ( 5tan beta)/( 1+ tan^(2) beta ) = (3 tan alpha )/( 1+ tan^(2) alpha)` Substituting `tan beta = 3 tan alpha`, we have `" " ( 5xx 3 tan alpha ) /( 1+9 tan^(2) alpha ) = ( 3tan alpha )/( 1+ tan^(2) alpha)` or `5 +5 tan^(2) alpha = 1+ 9 tan ^(2) alpha ` or `4 tan ^(2) alpha = 4` or `tan alpha = 1`, i.e., `tan beta = 3` `therefore tan alpha + tan beta = 4` |
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