1.

Aluminium crystallises in a face-centred cubic lattice. The edge length of the unit cell of aluminium is 4.05 x 10^-10m. What is the density of aluminium? (Atomic mass of Al=27)(a) 2700 kg m^-3(b) 3000 kg m^-3(c) 2400 kg m^-3(d) 2100 kg m^-3I have been asked this question by my college professor while I was bunking the class.My doubt stems from Solid State topic in portion Solid State of Chemistry – Class 12

Answer»

Right option is (a) 2700 kg m^-3

The EXPLANATION is: Given,

Atomic mass (M)=27 amu

For FCC structure, Z=4

Avogadro’s NUMBER (N0) = 6.02 X 10^23

Edge length of the Al unit cell (a)= 4.05 x 10^-10m

The density of aluminium (ρ) = (Z x M)/(a^3 X N0)

= (4 x 27)/((4.05 x 10^-10) ^3 x 6.02 x 10^23)

= 2700 kg m^-3.


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