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Aluminium phosphate is `100%` ionised in `0.01` molal aqueous solution . Hence , `DeltaT_(b) // K_(b)` is :A. `0.01`B. `0.015`C. `0.0175`D. `0.02` |
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Answer» Correct Answer - D `AlPO_(4)hArrAl^(3)+PO_(4)^(3-)` `i=1+x=2` `DeltaT_(b)="molality"xxK_(b)xxi=0.01xxK_(b)xx2` `:.(DeltaT_(b))/(K_(b))=0.02` |
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